8x^2+44x-104=0

Solution for 8x^2+44x-104=0 equation:

8x^2+44x-104=0

a = 8; b = 44; c = -104;
Δ = b2-4ac
Δ = 442-4·8·(-104)
Δ = 5264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5264}=\sqrt{16*329}=\sqrt{16}*\sqrt{329}=4\sqrt{329}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{329}}{2*8}=\frac{-44-4\sqrt{329}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{329}}{2*8}=\frac{-44+4\sqrt{329}}{16}
$